If the solution set of inequality (A-3) x ＞ 1 is 1 / 3 of X ＜ A-3, then the value range of a is 3Q

If the solution set of inequality (A-3) x ＞ 1 is 1 / 3 of X ＜ A-3, then the value range of a is 3Q

Inequality x ^ 2-3 (a + 1) x + 2 (3a + 1) for solution x

On the left side, the cross factorization of the formula is carried out
When [x - (3a + 1)] (X-2) 2, that is, when a > 1 / 3, the solution set of the inequality is: 2

Given that 7p ^ 2 + 3p-2 = 0, 2q ^ 2-3q-7 = 0, and PQ ≠ 1, find the value of (1 / P) + Q

7p^2+3p-2=0
Divide by - P ^ 2
2*(1/p)^2-3(1/p)-7=0
2q^2-3q-7=0
And PQ ≠ 1, that is, Q ≠ 1 / P
So Q and 1 / P are roots of the equation 2x ^ 2-3x-7 = 0
So 1 / P + q = 3 / 2