The square of x minus five and x plus six is less than zero to solve quadratic equation of one variable

The square of x minus five and x plus six is less than zero to solve quadratic equation of one variable


x²-5x+6



I also have a problem where the square of x minus five and x plus six is less than zero


x^2-5x+6



Integer solution X of equation (XX − 1) 2 + 6 = 5 (XX − 1)=______ ．


Let y = XX − 1, then y2-5y + 6 = 0, y = 2 or 3, XX − 1 = 2 or XX − 1 = 3, x = 2 or x = 1.5, x = 2 or 1.5 is the solution of the original equation, but the integer solution is x = 2, so the answer is x = 2

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