Bivariate linear equation: X / 3-y / 4 = x / 2 + Y / 3-10 = 3 (with process) There is another problem: when solving the equations {ax + by = 26, the correct solution is {x = 4) cx+y=6 y=-2 Because Xiao Ming wrongly wrote C, the solution is {x = 7} y=3 The correct values of Qiu a, B, C When {ax + by = 26 CX + y = 6, {x = 4, y = - 2 And the above question!

Bivariate linear equation: X / 3-y / 4 = x / 2 + Y / 3-10 = 3 (with process) There is another problem: when solving the equations {ax + by = 26, the correct solution is {x = 4) cx+y=6 y=-2 Because Xiao Ming wrongly wrote C, the solution is {x = 7} y=3 The correct values of Qiu a, B, C When {ax + by = 26 CX + y = 6, {x = 4, y = - 2 And the above question!

4a-2b=26 6a-3b=39
4c=8 c=2
7a+3b=26
13a=65 a=5
b=-3
So a = 5, B = - 3, C = 2

To solve the quadratic equation Y-X / 7-x + Y / 6 = 1 / 25 (x + y) - 2 (Y-X) = 1

7y/6-8x/7=1/2.49y-48x=21.147y-144x=63 7x+3y=1.3y+7x=1.147y+343x=49..487x=-14...x=-14/487 147y-343*14/487=49.y=195/487

If x.y of a quadratic equation of two variables satisfies that 3 / x + 1 equals 2 / y + 2 equals 2 / x + y, find the value of x.y
Please

(x+1)/3=(y+2)/2=(x+y)/2
x=2
y=0