Given the first-order function y = KX + B, when 0 ≤ x ≤ 2, the value range of the corresponding function value y is - 4 ≤ y ≤ 8, then the value of KB is______ .

Given the first-order function y = KX + B, when 0 ≤ x ≤ 2, the value range of the corresponding function value y is - 4 ≤ y ≤ 8, then the value of KB is______ .


(1) When k > 0, y increases with the increase of X, that is, the first-order function is an increasing function, when x = 0, y = - 4, when x = 2, y = 8, substituting into the analytic formula of first-order function y = KX + B, we get b = - 42K + B = 8, the solution is k = 6B = - 4, KB = 6 × (- 4) = - 24; (2) when k < 0, y decreases with the increase of X, that is, the first-order function is a decreasing function, when x = 0, y = 8, when x = 2, y = - 4, substituting into one The analytic formula y = KX + B of the secondary function is: B = 82k + B = − 4, the solution is k = − 6B = 8, KB = - 6 × 8 = - 48. So the value of KB is - 24 or - 48. So the answer is - 24 or - 48



It is known that the value range of the independent variable of a function is x greater than or equal to 2 less than or equal to 6, and the value range of the function is y greater than 5 less than 9


Let the first-order function y = ax + B, increase by degrees, draw and calculate the slope as 1, pass through the point (6,9), and obtain B = 3 by undetermined coefficient method, that is, the analytic formula of the first-order function is y = x + 3, X is greater than or equal to 2, and less than or equal to 6;
If decreasing, the analytic formula of the first-order function is y = - x + 11, X is greater than or equal to 2 and less than or equal to 6



When x is greater than or equal to 0, for the function y = - x (2 - x), find the value range of Y
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Urgent!


The value range of Y is Y > = - 1. Because y = x & sup2; - 2x = (x-1) & sup2;, it is a parabola with opening upward. When x = 1, the minimum value is - 1 and the maximum value is infinite. It can be seen that when x is greater than or equal to 0, y can get the minimum value, so the value range of Y is Y > = - 1