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How to find the determinant | a + B |? Let | a | = det (A1, A2, A3, A4) = 3, | B | = det (B1, A2, A3, A4) = - 5, and find | a + B|
det(a1+b1,a2+a2,a3+b3,a4+b4)
=det(a1,a2+a2,a3+b3,a4+b4)+det(b1,a2+a2,a3+b3,a4+b4)
=8det(a1,a2,a3,a4)+8det(b1,a2,a3,a4)
=24-40
=-16
Find determinant a b b b b b b b a
1. Add all columns to column 1
2. All lines minus line 1
Look at the effect
D= [a+(n-1)b](a-b)^(n-1)
The determinant | a + B | = | a | + | B |, right?
This is not right
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