There are several liters of 55% alcohol. After adding one liter of 80% alcohol, the concentration becomes 60%. To get 75% alcohol, 80% alcohol is needed. How many liters of 80% alcohol are needed to get 75% alcohol?

There are several liters of 55% alcohol. After adding one liter of 80% alcohol, the concentration becomes 60%. To get 75% alcohol, 80% alcohol is needed. How many liters of 80% alcohol are needed to get 75% alcohol?


Let x rise
Alcohol 55% X
Plus 1
Then 55% x + 1 * 80% = 60% (x + 1)
0.55x+0.8=0.6x+0.6
0.05x=0.2
x=4
Let y be added
That's 4 + y liters
Alcohol is 4 * 55% + 80% y = 75% (y + 4)
2.2+0.8y=0.75y+3
0.05y=0.8
y=16
A: add 16 liters



Mix 80% and 20% alcohol solution to make 150 kg of 60% alcohol solution. How many kg of these two alcohol solutions
What do mathematical geniuses do


The ratio of 80% 2 to 0% is (0.6-0.2): (0.8-0.6) = 2:1
So 80% of 150 △ 3 × 2 = 100 kg is needed
20% of 150-100 = 50 kg
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