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The radius of the bottom of the cone is reduced to 2 / 1 of the original, and the height of the high expansion road is 4 times of the original, and the volume remains unchanged? 1： If the volume of a cylinder is 120 cm & sup3; more than that of a cone with equal base and height, then the volume of a cylinder is 180 cm & sup3; 2： The diameter and height of the bottom surface of a cylinder are expanded to 2 times of the original, and the side area is expanded to 4 times of the original 3： The volume of a cube wood chip with 2 mm edge length is 6.28 DM & sup 3; 4： If the height of the cone is C decimeter, then the height of the original is 3 / 1 C decimeter How to list the above formula? You smart people teach me ~ write it all out, I will + 100 points
1. Let the diameter and height of the bottom surface of the cylinder be D and h respectively, then the side area s = π DH. If both the diameter and height of the bottom surface are increased by two times, then the side area s ′ = π × 2D × 2H = 4 π DH = 4S. 3. The diameter and height of the bottom surface of the largest cylinder is 2 mm, so the volume v = π × 1 & sup2
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