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Can you use the adjustment formula to calculate (3 + 2) (3 ^ 2 + 2 ^ 2) * (3 ^ 4 + 2 ^ 4) (3 ^ 8 + 2 ^ 8)?
（3+2）（3^2+2^2）*（3^4+2^4）（3^8+2^8）=1*（3+2）（3^2+2^2）*（3^4+2^4）（3^8+2^8）=(3-2)*（3+2）*（3^2+2^2）*（3^4+2^4）*（3^8+2^8）=(3^2-2^2)*（3^2+2^2）*（3^4+2^4）*（3^8+2^8）=(3^4-2^4)*（3^4+2^...
Using scientific counting method to calculate 3000700000
3000700000=3.0007×10^9
1 + 7 + 7 ^ 2 + 7 ^ 3 + 7 ^ 4. + 7 ^ 2004 + 7 ^ 2005 scientific notation
1+7+7^2+7^3+7^4.+7^2004+7^2005
=(1-7^2006)/(1-7)
=3.08*10^1694
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