There is a two digit number whose ten digit number is 5 larger than the one digit number, and whose two digit number is 5 larger than the sum of his two digit numbers Find this two digit number, 1 It's a mistake, but I already know how to do it=

There is a two digit number whose ten digit number is 5 larger than the one digit number, and whose two digit number is 5 larger than the sum of his two digit numbers Find this two digit number, 1 It's a mistake, but I already know how to do it=

You see if the title is copied correctly. It seems that there is no solution

For a two digit number, the number on the single digit is 5 larger than the number on the ten digit number, and the two digits are smaller than 28. Find the two digits

Let X be the one digit and X-5 be the ten digit
This two digit number is 10 (X-5) + x = 11x-50

There is a two digit number. The number on the one digit is 5 larger than that on the ten digit number. If the positions of the two digits are exchanged, then the sum of the new number and the original number is 143. Find the two digits

Let ten digits be x and one digit be (x + 5)
[10X+(X+5)]+[10(X+5)+X]=143
11X+5+10X+50+X=143
11X+10X+X=143-5-50
22X=88
X=4
X+5=4+5=9
Original two digit = 4 * 10 + 9 = 49
A: the double digit is 49
I hope you will be satisfied^_^