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The sum of each digit of a three digit number is 17. The ten digit number is larger than the one digit number. 1. If the hundred digit number of the three digit number is swapped with the one digit number to get a new three digit number, the new three digit number is 198 larger than the original three digit number
Let the original number be a, then the tens are a + 1, and the hundreds are 16-2a. According to the equation 100A + 10 (a + 1) + 16-2a-100 (16-2a) - (10a + 1) - a = 198, the solution is a = 6, then a + 1 = 7, 16-2a = 4. A: the original number is 476
For a two digit number, each digit is 2 more than the ten digit number. If you transpose the one digit number and the ten digit number, the new number is 2 times of the original number and 17 less. Find the original two digit number
Let X be the one digit number of the original number, then y be the ten digit number. According to the meaning of the question, we get: x = y + 22 (10Y + x) − 17 = 10x + y, and the solution is: x = 5Y = 3. Then the original two digit number is 35
The sum of all the three digit numbers is 17. The ten digit number is larger than the one digit number. 1
If a new three digit number is obtained, the new three digit number is 198 larger than the original three digit number
Suppose that the hundred of the three digit number is x, the ten digit number is y, and the one digit number is Y-1, then we can get: x + y + Y-1 = 17, that is, x + 2Y = 18. ① if the hundred of the three digit number is exchanged with the one digit number to get a new three digit number, then the new three digit number is 198 larger than the original three digit number
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