If s = 1 + 1 / 2 + 1 / 3 + 1 / 4 + 1 / 5 + 1 / 6 + 1 / 7 + 1 / 8 + 1 / 9 + 1 / 10, which two consecutive integers are between

If s = 1 + 1 / 2 + 1 / 3 + 1 / 4 + 1 / 5 + 1 / 6 + 1 / 7 + 1 / 8 + 1 / 9 + 1 / 10, which two consecutive integers are between

2 and 3

Square X4 of 1.3333-square x9 of 1.2222
How do you calculate it,

Square of 1.3333 4-square of 1.2222 9
=Square of (1.3333 Χ 2) - (1.2222 Χ 3)
=(2.6666-3.6666)Χ(2.6666+3.6666)
=-6.3332

Simplification of 1.2222's Square by 9-1.3333's Square by 4
Square of 1.2222 times 9-square of 1.3333 times 4
Simplification

The original formula = (1.2222 × 3) & #178; - (1.3333 × 2) & #178;
＝﹙1.2222×3＋1.3333×2﹚﹙1.2222×3－1.3333×2﹚
＝﹙3.6666＋2.6666﹚﹙3.6666－2.6666﹚
＝6.3332