The proposition "the middle line on the hypotenuse of a right triangle is equal to half of the hypotenuse". Is this proposition true? If it is a true proposition, please write the process of knowing, proving and proving; if it is a false proposition, please explain the reason; Write the inverse proposition of its proposition

The proposition "the middle line on the hypotenuse of a right triangle is equal to half of the hypotenuse". Is this proposition true? If it is a true proposition, please write the process of knowing, proving and proving; if it is a false proposition, please explain the reason; Write the inverse proposition of its proposition

This theorem is also correct. It is true proposition known: RT △ ABC, ∠ C = 90 °, D is the midpoint on the hypotenuse ab. CD = 1 / 2Ab the method of proving method n extends BC to e, making CE = CB, it is easy to prove that △ AEB is isosceles triangle, that is AE = ab. because C and D are the midpoint of the corresponding edge, De is the median line of △ AEB, so C

In a right triangle, how to prove the inverse theorem that the central line on the hypotenuse is equal to half of the hypotenuse
Given △ ABC, the middle line on the side of BC is equal to 1 / 2BC, it is proved that ∠ BAC = RT ∠

It is proved that: ∵ midline ad = BC / 2 ∵ ad = BD = CD ∵ C = CAD, ∵ B = ∵ bad ∵ C + ∵ B + ∵ cab = 180 ∵ cab = 90 ∵

The middle line on the hypotenuse of a right triangle is equal to half of the hypotenuse. Is there an inverse theorem?

Inverse theorem: if the center line of one side of a triangle is equal to half of that side, then the triangle is a right triangle and the angle opposite the side is a right angle