It is known that the trilateral lengths a, B and C of △ ABC satisfy the square of (a-5) + (B-12) + (C-13) = 0. Try to judge the shape of △ ABC and make it clear

It is known that the trilateral lengths a, B and C of △ ABC satisfy the square of (a-5) + (B-12) + (C-13) = 0. Try to judge the shape of △ ABC and make it clear

Because the square of (a-5) + (B-12) + (C-13) = 0,
So a = 5, B = 12, C = 13,
So delta ABC is a right triangle

What is the square of 3 4 5 3 = 4 + 5 13 = b = C

Square of 13 = 169
169-1=168
168/2=84
So 13 squared = 84 + 85
So B = 84, C = 85

The square of 3 plus the square of 4 equals the square of 5, and the square of 5 plus the square of 12 equals the square of 13?

(2n+1)^2+(2n^2+2n)^2=(2n^2+2n+1)^2