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A granite stone with school motto has a mass of 3.18 × 104 & nbsp; kg and a density of 2.65 × 103 & nbsp; The density of brick is known to be 2.05 × 103kg / m3, and the density of cement mortar in the base brick joint is the same as that of brick (G is 10N / kg) (1) The volume of granite stone; (2) the pressure of stone on base; (3) the ratio of stone to base and base to ground
(1) Volume of granite stone: v = m ρ = 3.18 × 104kg2.65 × 103kg / m3 = 12m3; answer: volume of granite stone is 12m3; (2) gravity of granite stone: G1 = m1g = 3.18 × 104kg × 10N / kg = 3.18 × 105N pressure of stone on base: P1 = f1s1 = g1s1 = 3.18 × 105n2.12m2 = 1.5
The mass of a granite stone with school motto is 31.8t and the density is 2.65 × 103kg / m3. It is erected on a horizontal base with a length of 4m, a width of 2M and a height of 0.5m (as shown in the figure). The contact area between the stone and the base is 2.12m2. The density of the known brick is 2.05 × 103kg / m3. The density of the cement mortar in the base brick joint is the same as that of the brick. (G is 10N / kg) Volume; (2) the pressure of stone to base; (3) the ratio of stone to base and base to ground
(1) The volume of granite stone: V stone = m stone, ρ stone = 31.8 × 103kg2.65 × 103kg / m3 = 12m3. A: the volume of granite stone is 12m3. (2) since the stone is placed on the horizontal base, the pressure of stone on the base is equal to the gravity of stone, that is, f stone = g stone = m stone, g = 31.8 × 103kg × 10N / kg = 3.18 × 105N, then the pressure of stone on the base: P stone = f stone, s Stone = 3.18 × 105n2.12m2 =1.5 × 105Pa. A: the pressure of stone on the base is 1.5 × 105Pa. (3) the gravity on the base: G base = m base, g = ρ base, V base, g = 2.05 × 103kg / m3 × (4m × 2m × 0.5m) × 10N / kg = 8.2 × 104n, the pressure of base on the ground: P base = FS base = g stone + G base, s base = 3.18 × 105N + 8.2 × 104n4m × 2m = 5 × 104pa, so the pressure ratio of stone to base and base on the ground: P base = 1.5 × 105Pa: 5 × 104pa PA = 3:1. A: the pressure ratio of stone to base and base to ground is 3:1
The mass of a granite stone with school motto is about 32t, standing on a horizontal base made of brick, 4m long, 2m wide and 0.5m high. The contact area between the stone and the base is about 2m & # 178. The density of the known brick is 2.05x10 & # 179; kggm & # 179;, and the density of the cement mortar in the base brick joint is the same as that of the brick. (g = 10N / kg)
Solution: 1. The pressure of stone on the base
2. The pressure of the base on the ground
1. P = f / s, f = g stone, m stone = 32t = 32000kg, and S = 2M2, so: P = mg / S = 32000 × 10 / 2 = 160000pa2, the pressure of the base to the ground is equal to the total weight divided by the stressed area: m block = ρ brick V, v = 4 × 2 × 0.5 = 4m3, ρ brick = 2050kg / m3, so: G block =
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