The weight of an elephant is 6000kg, and the landing area of each foot is 600cm2. Try to calculate the pressure of the elephant on the ground when standing. (G is 10N / kg)

The weight of an elephant is 6000kg, and the landing area of each foot is 600cm2. Try to calculate the pressure of the elephant on the ground when standing. (G is 10N / kg)


The pressure of elephant on the ground: F = g = mg = 6 × 103kg × 10N / kg = 6 × 104n, the area of elephant's four feet: S = 4 × 600cm2 = 2400cm2 = 0.24m2, the pressure of elephant on the ground: P = FS = 6 × 104n0.24m2 = 2.5 × 105Pa



The crawler is a bulldozer with a mass of 1.5 * 100000, and the contact area between each crawler and the ground is 1.25m2 (1)
Xiaoqiang lifts a 120N object with a pulley block at a constant speed and moves 6m at the free end of the rope within 2S. The mechanical efficiency of the pulley block is 80 / 100 (1) the work and power of Xiaoqiang (2) the tension of Xiaoqiang acting on the free end of the rope (analysis)


P=F/A=1.5*100000*9.8/1.25*2=588000Pa.



The weight of a terracotta warriors and horses is 1600n, and the area of the underground pedal is 1.6 × 10-2 square meters (G is 10N / kg)


From g = mg, M = g / g = 1600n / 10g = 160kg; pressure: P = f / s, in the horizontal plane, f = g, i.e. P = 1600n / 160m2 = 10 PA