m3(m-2n)=n3(2m-n)=? Factorization problem

m3(m-2n)=n3(2m-n)=? Factorization problem

m³(m-2n)+n³(2m-n) =m^4-2m³n+2mn³-n^4 =(m^4-n^4)-2mn(m²-n²) =(m²+n²)(m²-n²)-2mn(m²-n²) =(m²-n²)(m²-2mn+n²) =(m+n)(m-n)&su...

It is known that the square-2 + MX-3 of polynomial (m-2) XM is a quadratic trinomial of X, and the value of M is obtained

∵ the square of m-2 + MX-3 of polynomial (m-2) x is a quadratic trinomial of X
That is, (m-2) x ^ (M & # 178; - 2) + MX-3
The above polynomials are quadratic trinomials of X
∴m-2≠0 m²-2=2
The solution is m = - 2

Given that the m-th power of 2 multiplied by the m-th power of 4 is equal to the 18 th power of 2, find the value of M

2^m×4^m=2^18
2^m×(2²﹚^m=2^18
2^(m+2m)=2^18
3m=18
m=6