Given that f (x) = e ^ x-ax-1, if f (x) increases monotonically in the domain R, the value range of a is obtained Let f (x) = e ^ x-ax-1, 1. If f (x) increases monotonically in the domain R, find the value range of A 2. If f (x) decreases monotonically on (negative infinity, 0) and increases monotonically on [0, positive infinity), find the value of A

Given that f (x) = e ^ x-ax-1, if f (x) increases monotonically in the domain R, the value range of a is obtained Let f (x) = e ^ x-ax-1, 1. If f (x) increases monotonically in the domain R, find the value range of A 2. If f (x) decreases monotonically on (negative infinity, 0) and increases monotonically on [0, positive infinity), find the value of A

f′＝e^x-a
⒈ f′≥0↔a≤0.
2.a＝1

If the zeroth power of (x + 4) is 1, then the value range of X is

The value range of X is R (real number)
Any number can be taken

If (3x-1) 0 = 1, then the value range of X is______ ．

∵ (3x-1) 0 is meaningful, ∵ 3x-1 ≠ 0, ∵ x ≠ 13

When x < 0, the value range of y = (1 / 5) x power is?

When x ＜ 0, the value range of y = (1 / 5) x power is y ＞ 1; X = 0; y = (1 / 5) ° = 1; because y = (1 / 5) ^ x monotonically decreases 〈 y ＞ 1; Hello, I'm glad to answer for you, skyhunter 002 will answer for you. If you don't understand this question, please follow up. If you are satisfied, please remember to adopt it. If you have any other questions, please adopt it