In △ ABC, ab = AC, and the acute angle obtained by the intersection of the vertical bisector of AB and the line where the edge AC is located is 50 degrees, then what is the size of the base angle ∠ B of △ ABC?
When ∠ A is an acute angle, the acute angle obtained by the intersection of the vertical bisector of ∵ AB and the straight line of AC is 50 °, a = 40 °, B = 180 ° - A2 = (180 ° - 40 °) / 2 = 70 °; when ∠ A is an obtuse angle, the acute angle obtained by the intersection of the vertical bisector of
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