The minimum value of function y = sin ^ 2x + 2 / sin ^ 2x on (0. π / 2]

The minimum value of function y = sin ^ 2x + 2 / sin ^ 2x on (0. π / 2]


Y = x + 2 / X decreases at (0, √ 2)
And 0



What is the minimum value of the function f (x) = sin (2x - π / 4) in the interval [0, π / 2]?


∵x∈【0,π/2】
∴2x-π/4∈[-π/4,3π/4]
When 2x - π / 4 = - π / 4, the minimum value is sin (- π / 4) = - √ 2 / 2;
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The square of X - x + 1 / 2 x = 7. To find the fourth power of x plus the second power of X + 1 / 2 x, we need to use the reciprocal method


X/(X^2-X+1)=7,
7X^2-7X+7=X,
7x ^ 2-8x + 7 = 0 (the equation has no real root)
X + 1 / x = 8 / 7 (divide both sides by 7x)
∴(X+1/X)^2=64/49
X ^ 2 + 1 / x ^ 2 = - 34 / 49 (reason for no real root)
X^2/(X^4+X^2+1)
=1 / [x ^ 2 + 1 / x ^ 2 + 1] (both numerator and denominator are divided by x ^ 2)
=1/(-34/49+1)
=49/15.