It is known that a and B belong to (0, positive infinity), and 2C > A + B

It is known that a and B belong to (0, positive infinity), and 2C > A + B

It is known that a > 0, b > 0
Then a + B ≥ 2 √ (AB)
And 2C > A + B
So 2C > 2 (√ AB)
4c^2>4ab
c^2>ab

Let a + B = 2C be known and prove: ab ≤ C ^ 2

Because
0≤（a-b)^2
therefore
2ab≤a^2+b^2 ①
And because
a+b=2c
Square both sides at the same time
a^2+b^2+2ab=4c^2
Well organized
a^2+b^2=4c^2-2ab ②
① Substituting in (2)
2ab≤4c^2-2ab
Well organized
4ab≤4c^2
So ab ≤ C ^ 2

Given a square + b square + C square - ab-3b-2c + 4 = then a + B + C = what?

a²+b²+c²-ab-3b-2c+4=0
（a²-ab+1/4b²）+（3/4b²-3b+3）+（c²-2c+1）=0
a=1/2b,b=2,c=1
a+b+c=4.
If you don't know, ask me again, I'll be more detailed. I wish you progress in your study!

A and B start from AB and run in opposite directions. If a goes 28 kilometers ahead, then the distance ratio of a and B is 5:1
A and B start from AB and run in opposite directions. If a goes 28 kilometers ahead, then the distance ratio of a and B is 5: if B goes 28 kilometers ahead, then the distance ratio of a and B is 2: find the distance between ab.

Let a go x, B go y, and X + y + 28 be ab distance
（X+28）/Y=5/4
x/(y+28)=2/3
X = 72, y = 80
So the AB distance is 180 km

A car goes from place a to place B. when it is 16 kilometers away from the midpoint, the ratio of the distance traveled to the distance not traveled is 2:3. How many kilometers is the distance between a and B?
Please, please

16x2 ÷ (3-2) x (3 + 2) = 160km
A: the distance between a and B is 160 kilometers

When the car goes from place a to place B and passes by a certain place, the distance it has traveled is the remaining 3 / 5. When it goes for another 27 kilometers, the distance it has traveled is the remaining 3 / 2?

At the beginning:
Distance traveled: whole journey = 3: (3 + 5) = 3:8
Later:
Distance traveled: whole journey = 3: (3 + 2) = 3:5
whole course
=27 ÷ (3 / 5-3 / 8)
=27 △ 9 / 40
=120 km

Two cars of a and B leave the two cities at the same time. Two hours later, the two cars meet at the midpoint of 16 kilometers. At this time, the distance ratio of car a to car B is 3
The distance ratio between car a and car B is 3: how many kilometers does car a and car B travel per hour? (sorry) find the formula

A: 48
B: 64
Let the velocity of a be x, the velocity of B be y, and the whole course be s. then 2x + 2Y = s
The distance ratio between a and B is 3:4, so X

A car from a to B, has walked 108 kilometers, is the remaining three fourths of the distance, how many kilometers is the distance between a and B?
Write the formula and the reason

Setting: the distance between a and B is x kilometers
It is known that:
It's 108 kilometers. The rest of the way is x-108
According to the fact that walking 108 km is three fourths of the distance left, we get the following equation:
108=（x-108）×3/4
Solution
x=252
That's the answer

A car from a to B, after 720 kilometers, the ratio of the traveled distance and the not traveled distance is 3:2, how many kilometers is the distance from a to B?

720 × (3 + 2) / 3 = 1200 km
A: the distance from place a to place B is 1200 kilometers

From a to B, it takes one hour for a bus and 10 hours for a truck. Now the truck and the bus start from a and B at the same time, and they run in opposite directions. When they meet, they compare goods
From a to B, it takes 10 hours for a bus and 15 hours for a truck. Now, the truck and the bus start from a and B at the same time and run in opposite directions. When they meet, the bus just runs 240 kilometers. How many kilometers do a and B get together

Let the distance between AB and ab be x km
1/10∶1/15＝3∶2
3÷（2＋3）＝3/5
∴ x ×3/5＝240
x＝240×5/3
x＝400