In the triangle ABC, the opposite sides of the angles a, B and C are a, B and C respectively, and a + C / 18 = B-A / 7, C-B / C-A = 1 / 8 is used to find sinatan B
(a+c)/18=(b-a)/7,(c-b)/(c-a)=1/8,
∴7a+7c=18b-18a,8c-8b=c-a,
∴25a-18b=-7c,a=8b-7c,
∴a=5c/13,b=12c/13,
∴a^+b^=c^,
∴∠C=90°,
∴sinAtanB
=a/c*b/a
=5/13*12/5
=12/13.
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