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If the rational number AB satisfies the quadratic power of | 2a-b | + (3b + 2) = 0 a-b=__
A:
|The second power of 2a-b | + (3b + 2) = 0
Because: the absolute value and the square are greater than or equal to 0
So: when both are 0, and are 0
So:
2a-b=0
3b+2=0
The solution is: B = - 2 / 3
So: a = B / 2 = - 1 / 3
So: A-B = - 1 / 3 - (- 2 / 3) = 1 / 3
So: A-B = 1 / 3
Given that a = - y ^ 2 + AY-1, B = 2Y ^ 2 + 3ay-2y-1, and the value of polynomial 2a-b has nothing to do with the value of letter Y, the value of a is obtained
2A-B
=-2y²+2ay-2-2y²-3ay+2y+1
=(2-a)y-1
Independent of Y, then the coefficient of Y is 0
So 2-A = 0
a=2
The polynomial about X, y of the algebraic formula (A-2) x square + 92B + 1) xy-x + Y-7, if it does not contain quadratic term, try to find the value of 3a-8b?
If I guess correctly, it should be (A-2) x ^ 2 + 9 (2B + 1) xy-x + Y-7? If so, because there is no quadratic term, the coefficient of quadratic term is 0, A-2 = 0, 2b + 1 = 0, a = 2, B = - 0.5, 3a-8b = 10
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