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Given that a and B are rational numbers and that a and B satisfy the formula 2A + 3b √ 5 = B + a √ 5 + 5 - √ 5, find the value of a + B The sign that looks like a check sign is the root sign
2a+3b√5=b+a√5+5-√5
2a+3b√5=b+5+√5(a-1)
2a=b+5
3b=a-1
The solution is a = 14 / 5, B = 3 / 5
So a + B = 14 / 5 + 3 / 5 = 17 / 5
Given that a and B are rational numbers, and 2A + 3b √ 5 = B + a √ 5 + 5 - √ 5, find the value of a + B
Transfer (3b + A + 1) root 5 = b-2a + 5
∵ a non-zero irrational number must not be equal to a non-zero rational number
∴
3b+a+1=0
b-2a+5=0
Let me have it
It is known that the opposite number of rational number a is - 2. The rational number B is 2 apart from a on the number axis, and the value of 2A + 3b is obtained
Urgent, correct answer, 5 points
Because the opposite number of a is - 2, a = - (- 2) = 2
Because the rational number B is 2 units of length away from a on the number axis, B = 2-2 = 0, or B = 2 + 2 = 4
When B = 0, 2A + 3B = 2 * 2 + 3 * 0 = 4
When B = 4, 2A + 3B = 2 * 2 + 3 * 4 = 4 + 12 = 16
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