What's the solution of one fifth plus x equals nine twentieth

What's the solution of one fifth plus x equals nine twentieth


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Given that ABC is a positive number, and one part of a + one part of B is equal to negative one part of a + one part of B, find the value of square of B part of a + square of a part of B


What does it have to do with C?
And there's something wrong with the title
1 / A + 1 / b = - 1 / A + B, that is, 1 / A + 1 / B + 1 / A + B = 0
ABC are all positive numbers. How can the sum of 1 / A, 1 / B, 1 / A + B be 0?
There is no solution to this problem!



In ABC, if we know that the square of a is one third of the square of B is one fourth of the square of C, then the degree of angle B is -


According to the cosine theorem: CoSb = (A & # 178; + C & # 178; - B & # 178;) / 2Ac = 2A & # 178; / 4A & # 178; = 1 / 2, so the angle B = 60 degrees