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A △ 6 / 7 = B × 6 / 5 = C × 5 / 6, where ABC is a natural number and is not zero, the three numbers of ABC are arranged in the order from small to large
6/5>6/7>5/6
So B
ABC is not a natural number with zero, and a is greater than C and greater than B. please arrange a in 6 / A, B in 6 / B and C in 6 / C from small to large
6 of a, 6 of C, 6 of B
a. B and C are natural numbers, a × B = 221, B × C = 187, C × a = 143, then a + B + C=______ ．
Because the factors of 221 are: 1, 13, 17, 221187 are: 1, 11, 17, 187143 are: 1, 11, 13, 143, we get: a = 13; b = 17; C = 11a + B + C = 13 + 17 + 11 = 41, or 221 = 13 × 17187 = 17 × 11143 = 11 × 13, according to the above formula, we can judge that a = 13, B = 17, C = 11, so a + B + C = 41, so the answer is: 41
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