Given that AB is opposite to each other, CD is reciprocal to each other, and the absolute value of X is equal to twice its opposite number, what is the value of X + abcdx + A + BCD?

Given that AB is opposite to each other, CD is reciprocal to each other, and the absolute value of X is equal to twice its opposite number, what is the value of X + abcdx + A + BCD?

That is, a + B = 0
cd=1
|x\=-2x
So x = 0
So the original formula = 0 + 0 + 0 + 1 = 1

Given that a, B are opposite numbers, C, D are reciprocal numbers, the absolute value of X is equal to twice of its opposite number, find the value of X × x × x + abcdx + A + BCD

|x|＝－2x x＝0 cd＝1 a＋b＝0
x³＋abcdx＋a＋bcd＝a＋bcd＝a＋b＝0

a. B is opposite to each other, C and D are negative reciprocal to each other, the absolute value of x = 2 times of its opposite number, find x ^ 3 + abcdx + a-bcd

x^3+abcdx+a-bcd
=o^3+0+(a+b)
=0