A kind of "Jinlongyu" brand edible blend oil is sold on the market. The bottle is marked with "5L". It is known that the density of the blend oil in the bottle is A kind of "Jinlongyu" brand edible blend oil is sold on the market. The bottle is marked with "5L". It is known that the density of the blend oil in the bottle is 0.92 × 10 3 kg / M 3. What is the mass of the oil in the bottle? If half of the blend oil is used up, what is the density of the remaining half bottle

A kind of "Jinlongyu" brand edible blend oil is sold on the market. The bottle is marked with "5L". It is known that the density of the blend oil in the bottle is A kind of "Jinlongyu" brand edible blend oil is sold on the market. The bottle is marked with "5L". It is known that the density of the blend oil in the bottle is 0.92 × 10 3 kg / M 3. What is the mass of the oil in the bottle? If half of the blend oil is used up, what is the density of the remaining half bottle


*It's a multiplication sign. 10 ^ 3 is the power of 10
5L=0.005m^3
From ρ = m / V to M = ρ v = 0.92 * 10 ^ 3kg / m ^ 3 * 0.005m3 = 4.6kg
6 kg
The density of the remaining half bottle of blended oil is still 0.92 * 10 ^ 3kg / m ^ 3
Format may be a bit nonstandard, anyway, the idea should be like this, according to your teacher's answer format to change