500 cubic meters of water tank production, steel plate thickness of 10 mm, how much steel plate, weight

500 cubic meters of water tank production, steel plate thickness of 10 mm, how much steel plate, weight


It depends on the shape of your water tank. Different shapes need different steel plate surface connection. As long as you know the surface area of the water tank, you can know how many square steel plates you need, and the thickness. When you know the density of the steel plate, you can know the weight of the steel plate
If it is a cube (with a cover) and the side length is a, then a * a * a = 500, we can work out what a is, and the area of steel plate needed is 6A * a



Uncle worker made a cuboid water tank with five pieces of steel plates. The ratio of the length, width and height of the water tank is 4:2:3? How many liters of water can the tank hold at most? (the thickness of steel plate is not included)


Because the cuboid's length: width: height = 4:2:3, width = 12, height = 34, and its length is 8 decimeters, so its width is 12 × 8 = 4 (decimeters), and its height is 34 × 8 = 6 (decimeters). Therefore, the water tank's length, width and height are 8 decimeters, 4 decimeters and 6 decimeters, so the area product of steel plate required is: (8 × 4 + 4 × 6 + 6 × 8) × 2-8 × 4, = (32 + 24 + 48) × 2-32, = 104 × 2-32, = 208-32, =176 (square decimeter); the volume of water tank: 8 × 4 × 6, = 32 × 6, = 192 (cubic decimeter), = 192 (liter); answer: this water tank is made of 176 square decimeter steel plate at least, and the maximum capacity of this water tank is 192 liters



Uncle worker made a cuboid water tank with five pieces of steel plates. The ratio of the length, width and height of the water tank is 4:2:3? How many liters of water can the tank hold at most? (the thickness of steel plate is not included)


Because the cuboid's length: width: height = 4:2:3, width = 12, height = 34, and its length is 8 decimeters, so its width is 12 × 8 = 4 (decimeters), and its height is 34 × 8 = 6 (decimeters). Therefore, the water tank's length, width and height are 8 decimeters, 4 decimeters and 6 decimeters, so the area product of steel plate required is: (8 × 4 + 4 × 6 + 6 × 8) × 2-8 × 4, = (32 + 24 + 48) × 2-32, = 104 × 2-32, = 208-32, =176 (square decimeter); the volume of water tank: 8 × 4 × 6, = 32 × 6, = 192 (cubic decimeter), = 192 (liter); answer: this water tank is made of 176 square decimeter steel plate at least, and the maximum capacity of this water tank is 192 liters



The water tank is made of steel plate with a width of at least 3:8 square meters? How many liters of water can the tank hold at most? (the thickness of steel plate is not included)


Because the cuboid's length: width: height = 4:2:3, width = 12, height = 34, and its length is 8 decimeters, so its width is 12 × 8 = 4 (decimeters), and its height is 34 × 8 = 6 (decimeters). Therefore, the water tank's length, width and height are 8 decimeters, 4 decimeters and 6 decimeters, so the area product of steel plate required is: (8 × 4 + 4 × 6 + 6 × 8) × 2-8 × 4, = (32 + 24 + 48) × 2-32, = 104 × 2-32, = 208-32, =176 (square decimeter); the volume of water tank: 8 × 4 × 6, = 32 × 6, = 192 (cubic decimeter), = 192 (liter); answer: this water tank is made of 176 square decimeter steel plate at least, and the maximum capacity of this water tank is 192 liters



A cuboid water tank is 1.2 meters long, 1 meter wide and 0.8 meters high. The water surface in the water tank is 0.5 meters high. How much is the water in the water tank


1.2 × 1 × 0.5 = 0.6 square meter = 60 square decimeter (liter)



A cuboid iron sheet without cover is 1 meter long and 4 decimeters high. How many square meters of iron sheet is needed to make such a water tank so that the water tank can hold water
Less kg (1 kg per cubic decimeter of water)


1*5+5*4*2+1*4*2=53
1*5*4=20



How to calculate the meter of a ton of steel plate with thickness of 0.18


Volume is equal to mass divided by density
Length equals volume divided by height divided by width
It should be calculated like this, but I don't know the width. If you know, you can calculate it yourself



Bearing 600 tons of weight, steel plate span for length and width of 1 meter, thickness should be how many mm, can give the best calculation, urgent


Assuming that 600 tons of goods are steel, its volume is 600 / 7.85 = 76.43m ^ 3, and the bearing area is only 1 × 1 = 1 m2. Therefore, the 600 tons of steel should be 7.643m high



The thickness is 0.007m, the width is 1m and the length is 1m. What's its weight?


Directly find a scale or calculate the volume of the object with length × height × width, check the density of the material, and then calculate the weight of the object with volume × density!



A cube steel block with an edge length of 6 decimeters is melted into a steel plate with a length of 24 decimeters and a width of 18 decimeters


6 × 6 × 6 = 216 (cubic decimeter)
216 / 24 / 18 = 0.5 (decimeter)
=5 (CM)