If the solution of equation a (x + C) with square + B = 0 is X1 = - 1 and X2 = 1, then the solution of equation a (x + c-2013) with square + B = 0 is X1 = - 1 and X2 = 1

If the solution of equation a (x + C) with square + B = 0 is X1 = - 1 and X2 = 1, then the solution of equation a (x + c-2013) with square + B = 0 is X1 = - 1 and X2 = 1

According to the meaning of the title:
x1=x3-2013=-1,x2=x4-2013=1
The solution is: X3 = 2012, X4 = 2014
So: the solution of equation a (x + c-2013) + B = 0 is x = 2012 or x = 2014

If X1 and X2 are two of the equations X & # 178; + X-1 / 2007 = 0, and X1 = λ X2, then λ & # 178; + 2009 λ=

X1 and X2 are two parts of the equation x ^ 2 + X-1 / 2007 = 0
x1+x2=-1 1
x1x2=-1/2007 2
x1=ax2 3
3 into 12
ax2+x2=-1 x2=-1/(a+1) 4
ax2^2=-1/2007 5
Substitute 4 for 5
(^ 2) / (2007 + 1) * / 1
2007a=-(a+1)^2
(a+1)^2+2007a=0
Dai Jian gets
a^2+2009a=-1

It is known that α and β are two of the equations X & # 178; + 2008x + 1 = 0, then the value of (α & # 178; + 2009 α + 1) (1 + 2009 β + β & # 178;) is?

（α²+2009α+1）（1+2009β+β²）
=(α²+2008α+1+α)(β²+2008β+1+β)
=αβ
=1