When x − YX + y = 2, the value of the algebraic expression x − YX + y-2x + 2yx − y is______ .

When x − YX + y = 2, the value of the algebraic expression x − YX + y-2x + 2yx − y is______ .


∵ x − YX + y = 2, ∵ X-Y = 2 (x + y), ∵ x − YX + y-2x + 2yx − y = 2 (x + y) x + Y-2 (x + y) 2 (x + y) = 2-1 = 1, so the answer is: 1



It is known that X1 and X2 are two of the equations x ^ 2-4x + 2 = 0, and the value of (x2-x2) ^ 2 can be obtained by Weida's theorem


X1 and X2 are two parts of the equation x ^ 2-4x + 2 = 0, then
X1 + X2 = 4
X1X2 = 2
(X2-X2)^2 = (X1 + X2)^2 - 4X1X2 = 4^2 - 4*2 = 8



When x = 2011, find the value of the algebraic formula LX + 1 − 2xx2 − 1


When x = 2011, the original formula = - 12011 − 1 = - 12010