Let f (x) = 2 − x − 1, X ≤ 0x12, x > 0, if f (x0) > 1, then the value range of x0 is______ ．

① When x0 ≤ 0, we can get 2-x0-1 ＞ 1, that is, 2-x0 ＞ 2, so - x0 ＞ 1, we can get x0 ＜ - 1; when x0 ＞ 0, x00.5 ＞ 1, we can get x0 ＞ 1

① When x0 ≤ 0, we can get 2-x0-1 ＞ 1, that is, 2-x0 ＞ 2, so - x0 ＞ 1, we can get x0 ＜ - 1; when x0 ＞ 0, x00.5 ＞ 1, we can get x0 ＞ 1

Let f (x) = ① 2 ^ - X-1, (x ≤ 0), ② x ^ 1 / 2, (x > 0). If f (x0) > 1, find the value range of x0

When your X is less than or equal to 0, the function is: = 2 ^ (- x-1)?
I think it's x0 > 1 or x0

8X-4=3.5+5X
8x-5x=3.5+4
3x=7,5
x=2.5

5x-3.8x=1.44
1.2x=1.44
x=1.44/1.2
x=1.2

5x^2-8x+3=0
(5x-3)(x-1)=0
So x = 3 / 5 or x = 1

5x=8x-8.1
8x-5x=8.1
3x-8.1
x=8.1÷3
x=2.7

0.8x-0.5x=0.3
(0.8-0.5)x=0.3
0.3x=0.3
x=1

5x+8x=260
13x=260
x=260/13
x=20

(5x+20)/8x=3/4
Solution 5x + 20 = (3 / 4) * 8x
5x+20=6x
20=6x-5x
x=20