The known function f (x) = ax ^ 3-cx, - 1

The known function f (x) = ax ^ 3-cx, - 1

(1) If a = 4, C = 3, f (x) = 4x ^ 3-3x
The derivation is: F '(x) = 12x ^ 2-3
Let f '(x) = 0, that is: 12x ^ 2-3 = 0
The solution is: x = ± 1 / 2, in line with the meaning of - 1

(1) If the cube root x = 4, then x =?, (2) 27x cube-8 = 0

（1）x=64
（2）-54

1. (2-x) square = 256, find x =? 2.1/4 (2x + 1) cube = 54, find x =?

(2－)²=256
(x－2)²=256
X-2 = 16 or X-2 = - 16
The result is: x = 18 or x = - 14
(1/4)(2x＋1)³=54
(2x＋1)³=216
2x＋1=6
x=5/2

2x cube-6 = 4 / 3 to find the value of X

2x²—6=4/3
x²=8/27
x³=(2/3)³
x=2/3

The cube of 2x of 4 is equal to the cube of X + 1 of 8. Find the value of X

The cube of 2x of 4 is equal to the 12x power of 2, and the cube of X + 1 of 8 is equal to the 9 (x + 1) power of 2, then 12x = 9 (x + 1), that is, x = 3

Cube of 2x - 6 = 3 / 4
Answer process!!!

2x^3-6=3/4
2x^3=3/4+6
2x^3=27/4
x^3=27/4÷2
x^3=27/8
x=3/2

2X (1 / 4 x-1) - (2x-1) (- 1-2x) calculation

148947857757866

27x cube = - 125 x =? 2 [X-1] Cube = 4 x =?

Cube of 27x = - 125
Cube of x = - 125 / 27
Cube of x = - (5 / 3) ^ 3
x=-5/3
Cube of 2 [X-1] = 4
Cube of [X-1] = 2
x-1=2^(1/3)
x=1+2^(1/3)
Maybe it's your fault, if it is
Cube of [X-1] = 8
x-1=2
x=3

Cube of (1-2x) = 8 to find x

Cube of (1-2x) = 8
1-2x=2
2x=1-2
2x=-1
x=-1/2

(2x) cubic = - 8

（2x-1）?=-8
It's Square on both sides
2x-1=-2
2X=-1
X=-1/2
Is that ok?