C language. There is a function y = x (x)

C language. There is a function y = x (x)


#include
void main()
{
float x,y;
scanf("%f",x);
if(x=1&&x



The function f (x) = x ^ 3 + BX ^ 2 + CX + 2 has extremum when x = 1


When x = 1, f (1) '= 3 + 2B + C = 0;
Then f (1) = 1 + B + C + 2 = 6, two equations are established simultaneously, B = - 6, C = 9



If the odd function FX = AX3 + bx2 + CX has an extreme value at x = 1 / A, then AC + 2B


Because f is an odd function, B = 0. F '(x) = 3ax ^ 2 + C,
f'(1/a)=0,3/a+c=0,ac=-3.ac+2b=-3.



Square of 1 + 3 + cube of 2 + 5 + 4-cube of 2


1+9+2+5+16-2=21



Find the unknown X / 6 = 40%


x/6=40%
x=0.4*6
x=2.4
Come on (⊙ o ⊙) Oh



14 * (x / 2) 2 * x = 40, X is unknown,
X is accurate to 0.1


3.14*x/2*2*x=40
3.14 * x square = 40
X = under root (40-3.14)



1.15x+7x=66
2.9x-8x=15.8
3.7.5x + 2.5x = 2 and 1 / 2
4.52x-4x=120
5.7.2-x=49.6
6.75+8x=125
If you want to find the formula, it can be as simple as possible


1.15x + 7x = 6622x = 66x = 32.9x-8x = 15.8x = 15.83.7.5x + 2.5x = 2 / 2 110x = 5 / 2x = 1 / 44.52x-4x = 12048x = 120x = 2.55.7.2-x = 49.6x = 49.6-7.2x = 42.46.75 + 8x = 1258x = 125-758x = 50x = 25 / 4



Find the unknown x.2x + 714 = 5x-234 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 4.5:127 = 113: (4-x)


(1)2x+714=5x− 234,    2x+714−2x=5x− 234−2x,         3x− 234=714,    3x-234+234=714+234,  &n...



How to set the unknowns for one variable linear equation? X-3 (x-3 (X-9)) = 9 (X-9)
Who can tell me


It's really sweat to see your question. It's estimated that the questioner is still at the level of junior high school. No special meaning. Everyone has a young age. Just kind-hearted correction, the way you write equations is not the proper format of a mathematical formula (I know you can write them with a pen). The proper way to write your formula is: X -



The third power of (2x-1) = 0.729, x = what


Solution
The third power of (2x-1) = 0.729
That is, the third power of (2x-1) = the third power of 0.9
∴2x-1=0.9
∴2x=1.9
∴x=0.95