Using elementary row transformation to find the inverse matrix of a matrix the first row 0 2 - 2 - 4 the second row 1273 the third row 0 32 - 1 the fourth row 1130

Using elementary row transformation to find the inverse matrix of a matrix the first row 0 2 - 2 - 4 the second row 1273 the third row 0 32 - 1 the fourth row 1130

The premise of finding the inverse matrix is that the matrix is reversible. The value of the determinant you give is 0, which is irreversible

Find the rank of the matrix: the first line 1 - 13 - 43, the second line 3 - 35 - 41, the third line 2 - 23 - 20, the fourth line 3 - 34 - 2 - 1

The rank of the matrix is 2
1 -1 3 -4 3
0 0 -4 8 -8
0 0 -3 6 -6
0 0 -5 10 -10
Continue to simplify
1 -1 3 -4 3
0 0 1 -2 2
0 0 0 0 0
0 0 0 0 0

The first line is 1-13-43, the second line is 3-35-41, the third line is 2-23-20, and the fourth line is 3-34-2-1

1 -1 3 -4 3
3 -3 5 -4 1
2 -2 3 -2 0
3 -3 4 -2 -1
r4-r2,r2-r1-r3,r3-2r1
1 -1 3 -4 3
0 0 -1 2 -2
0 0 -3 6 -6
0 0 -1 2 -2
r2*(-1),r1-3r2,r3+3r2,r4+r2
1 -1 0 2 -3
0 0 1 -2 2
0 0 0 0 0
0 0 0 0 0