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The first line is 120, the second line is 21 - 1, and the third line is 311. It is troublesome to write out the specific calculation process
(A,E)=
1 2 0 1 0 0
2 1 -1 0 1 0
3 1 1 0 0 1
r2-2r1,r3-3r1
1 2 0 1 0 0
0 -3 -1 -2 1 0
0 -5 1 -3 0 1
r3-2r2
1 2 0 1 0 0
0 -3 -1 -2 1 0
0 1 3 1 -2 1
r1-2r3,r2+3r3
1 0 -6 -1 4 -2
0 0 8 1 -5 3
0 1 3 1 -2 1
r2*(1/8),r2r3
1 0 -6 -1 4 -2
0 1 3 1 -2 1
0 0 1 1/8 -5/8 3/8
r1+6r3,r2-3r3
1 0 0 -1/4 1/4 1/4
0 1 0 5/8 -1/8 -1/81
0 0 1 1/8 -5/8 3/8
The inverse matrix is 3 * 3 on the right
Is a matrix equal to the original matrix after elementary transformation? For example, is the identity matrix and 001 010 100. The same matrix?
The equality of two matrices means: 1. The same type (the number of rows and columns are the same); 2. The corresponding components are the same
So the matrix after elementary transformation is not equal to the original matrix, not the same matrix
Let a = {010 20-1 341}, I = {100 010 001}, find a + I
Find {a + I} upper Right-1
A+I =
1 1 0
2 1 -1
3 4 2
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