By using the elementary row transformation of matrix, the inverse matrix of square matrix 2231 - 10 - 121 is obtained

By using the elementary row transformation of matrix, the inverse matrix of square matrix 2231 - 10 - 121 is obtained

The solutions are: (0, 2, 2, 0, 2-0, 2-0, 2-0, 1-0, 2-0, 2-0, 1-0, 2-0, 1-0, 2-0, 1-0, 2-0, 2-0, 2-0, 1-0, 2-0, 2-0, 1-0, 3-0, 2-0, 1-0, 2-0, 2-0, 2-0, 1, 3-0, 1, 2-0, 2-0, 1, 2-0, 2-0, 1, 2-0, 1, 1, 1, 1, 1, 3, 1

By using the elementary transformation of matrix, we can find the square matrix of inverse matrix

3 2 1 1 0 03 1 5 0 1 03 2 5 0 0 13 2 1 1 0 00 -1 4 -1 1 00 0 4 -1 0 13 2 1 1 0 00 1 -4 1 -1 00 0 1 -1/4 0 1/43 2 0 5/4 0 -1/40 1 0 0 -1 10 0 1 -1/4 0 1/43 0 0 5/4 2 -9/40 1 0 0 -1 10 0 1 -1/4 0 1/41 0...

By using the elementary row transformation of matrix, the inverse matrix of the following matrix is obtained
3 -1 0
-2 1 1
1 -1 4

When finding the inverse matrix of a matrix with elementary row transformation, that is to say, change the matrix (a, e) into the form of (E, b) with row transformation, then B is equal to the inverse of A. here (a, e) = 3 - 10100 - 2110101 - 14001, the first row minus the third row × 3, the second row plus the third row × 202 - 1210 - 30 - 190121 - 1