Let {an} satisfy A0 = a, a (n + 1) = can + 1-C, where a and C are real numbers and C is not equal to 0 Formula for finding general term Let a = 1 / 2, C = 1 / 2, BN = n [1-an}, find the first n terms of BN and Sn
a(n+1)=can+1-c
a(n+1)-1=c(an-1)
a(n+1)-1/(an-1)=c
So an-1 is an equal ratio sequence
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