Let LG2 = a, Lg3 = B. use a, B to express LG10 (senior one mathematics)

Let LG2 = a, Lg3 = B. use a, B to express LG10 (senior one mathematics)


Using LG2 = a condition
log(2)10=log(2)5+1=1/a
log(2)5=1/a-1
log(2)10=1/a
So lg5 = 1-A
lg10=lg2+lg5=a+1-a=1



Calculate LG25 + LG2 * LG50 + (LG2) ^ 2
The answer is that = (LG2) ^ 2 + (1 + lg5) * LG2 + lg5 ^ 2 = (LG2 + lg5 + 1) LG2 + 2lg5 = (1 + 1) LG2 + 2lg5 = 2 (LG2 + lg5) = 2
Why is it (1 + lg5) LG2


lg2*lg50=lg2*(lg5*10)=lg2*(lg5+lg10)=lg2*(lg5+1)