Given that F & nbsp; (x + 1) is odd, F & nbsp; (x-1) is even, and F & nbsp; (0) = 2, then f & nbsp; (2012) = () A. -2B. 0C. 2D. 3

Given that F & nbsp; (x + 1) is odd, F & nbsp; (x-1) is even, and F & nbsp; (0) = 2, then f & nbsp; (2012) = () A. -2B. 0C. 2D. 3


Because the function f (x + 1) is an odd function, if f (x + 1) = - f (- x + 1) let t = x + 1, then f (T) = - f (2-T) ∵ if f (x-1) is an even function ∵ f (x-1) = f (- x-1), let X-1 = t, then f (T) = f (- T-2) ∵ f (- T-2) = - f (- t + 2) let - T-2 = m, then f (m) = - f (...)