The sum of three consecutive natural numbers is less than 15. How many natural arrays are there in total? Write them separately

The sum of three consecutive natural numbers is less than 15. How many natural arrays are there in total? Write them separately

012,123,234,345

How many groups of natural numbers such as the sum of three continuous natural numbers less than 15
How many groups of natural numbers such as the sum of three continuous natural numbers less than 15? Find them out respectively

x+x+1+x+2

Given a = {the square of x-3x + 2 = 0}, B = {the square of X | x-2x + A-1 = 0} and a ∩ B = B, find a

So a = (2,1) if B is an empty set, then Δ is less than 0, then a is greater than 2; if B is not an empty set, then 1: Δ = 0, a = 2; substituting X1 into b set, then a = - 1, 2: Δ = 0, a = 2, substituting x2 into b set, then a = 23: Δ is greater than 0, then a is less than 2, substituting X1 and X2 into b set

If we change the quadratic trinomial 2x ^ 2-3x-4 into a polynomial with (x-1) as the element, we can get 2x ^ 2-3x-4 = a (x-1) ^ 2 + B (x-1) + C, and find a, B, C

This kind of problem can be solved by the idea of "cong"
2x²-3x-4=2(x²-2x+1)+x-6=2(x-1)²+(x-1)-5
So a = 2, B = 1, C = - 5
We can also make x = 1, x = 0, x = 1, and then solve a, B, C by simultaneous equations

If we change the quadratic trinomial 2 times the square of x-3x-4 into a polynomial with X-1 as the element, we can get 2 times the square of x-3x-4 = the square of a (x-1) + B (x-1) + C, and find a, B, C

a=2 b=1 c=-5

Mathematical problems: given that f (x) = the square of X - 3x + 4, G (x) = the square of 2x - x + 1, P (x) = the square of X + X-1 problems: (1)
Mathematical problems: F (x) = the square of X - 3x + 4, G (x) = the square of 2x - x + 1, P (x) = the square of X + X-1
Problem: (1) find half f (x) + quarter g (x) + P (x)
(2) When x = 1, find f (x) - G (x) + P (x)
Ask for clear process

（1）（1/2)f(x)+(1/4)g(x)+p(x)
=(x^2-3x+4)/2+(2x^2-x+1)/4+x^2+x-1
=(1/4)(2x^2-6x+8
.2x^2-x+1
.4x^2+4x-4)
=(1/4)(8x^2-3x+5)
=2x^2-(3/4)x+5/4.
(2)f(1)-g(1)+p(1)=2-2+1=1.

The 201 th power of (- 2) plus the 200 th power of (- 2) why the 200 th power of (- 2) * (- 2) + the 200 th power of (- 2)

Because: the square of a is equal to a * a
The cube of a is equal to a * a * a
The 201 th power of (- 2) plus the 200 th power of (- 2) why the 200 th power of (- 2) * (- 2) + the 200 th power of (- 2)
That is, the 201 th power of (- 2) is equal to the 200 th power of (- 2) * (- 2)
The 7th power of a is equal to the 3rd power of a * the 4th power of a, and the base number of a is constant

(5) How much is the power of 200 minus (1 / 5) 201?

(1 / 5) the power of 201 is close to 0
(5) To the power of 200 minus (1 / 5) to the power of 201
=5 to the power of 200

How to compare the negative 0.1 power of 0.8 with the negative 0.2 power of 0.8

It can be converted to the reciprocal of 0.8, the power of 0.1 and 0.2 of 1.25. 1.25 is greater than 1, so the power of 0.2 is larger

What is the N-1 power result of log with 3 as the base

n-1