Function judging parity Y = half plus the reciprocal of the x power of a, judge the parity, folks!

Function judging parity Y = half plus the reciprocal of the x power of a, judge the parity, folks!

F (x) = 1 / 2 + 1 / A ^ x (a > 0, a ^ x > 0) f (- x) = 1 / 2 + 1 / A ^ (- x) = 1 / 2 + A ^ x if f (x) = f (- x), then 1 / A ^ x = a ^ x a ^ x = 1 x = 0 if f (x) = - f (- x), then 1 / 2 + 1 / A ^ x = - 1 / 2-A ^ x 1 + 1 / A ^ x + A ^ x = 0 a ^ x > 0. The above formula is not true. So y is not odd or even

What is the parity of the function f (x) = xsinx?

The domain of original function is from positive infinity to negative infinity
Because for every x in the domain, f (- x) = - xsin (- x) = - x-sinx = xsinx = f (x)
So the original function is even

Is the function y = cosx odd or even?

Of course, it is even function. First, y = cosx = cos (- x) is even function
Second: his image is symmetrical about the Y axis, and it can also be concluded that it is an even function

Is y = x 1 / 2 times cosx odd or even or even
It is odd and even, not odd and not even?

Because the definition field of function is any real number with X not equal to 0, it is symmetric about the origin
Let f (x) = 1 / X be an odd function, f (- x) = - f (x), G (x) = cosx be an even function, and G (- x) = g (x)
Then f (x) = f (x) * g (x)
F(-x)=f(-x)*g(-x)
=-f(x)*g(x)
=-F(X)
So it's an odd function

Is y = secx-7 odd or even

Secx = 1 / cosx, directly into sec (- x) = 1 / cosx. So this is an even function

1 / cosx = secx?

Yes, SEC represents the secant in trigonometric function. The ratio of the hypotenuse of a right triangle to the adjacent edge of an acute angle is called the secant of the acute angle. It is represented by SEC (angle), such as secx, where X represents the angle (which can be expressed in degrees or radians). The Secant and cosine are reciprocal, that is, SEC θ = 1 / cos θ, so there is 1 / cos X

Find whether y = INX - | secx | is an odd or even function,
And y = | INX | - secx

y=f(x)=inx-|secx|
If INX is meaningful, then x > 0, - X

Odd function or even function of y = | LNX | - secx?

Even function, f (- x) = / ln (- x) / - sec (- x) = / LNX / - secx = f (x), so it is even function

Common even functions: C, x ^ 2, x ^ 2n, | x |, cosx, secx, e ^ x ^ 2, SiNx ^ 2, CHX
What function is C?

C is a constant
Do not understand, welcome to ask

The domain of y = 2sinx + 1 / 2sinx-1 and y = (1 + SiNx) (1 + cosx)

1, X is not equal to 0 + k * Pai 2