The sum of three consecutive natural numbers is less than 15. Please write out how many groups there are in such a natural array

The sum of three consecutive natural numbers is less than 15. Please write out how many groups there are in such a natural array

(0,1,2),
(1,2,3),
(2,3,4),
(3,4,5),
There were 4 groups

If f (x power of 3) = x / 4 times log 3 with base 2 plus 250
So, f (2) + F (4) + F (8) + +What does f (to the eighth power of 2) equal?
The topic is a little tangled, please be patient,

Answer: let x = log log log 2 ^ k with base 3 in 2009, then the original formula F (3 ^ x) = x / 4 * log log log 2 + 250 becomes f [3 ^ (log 2 ^ k with base 3)] = log log 2 ^ k with base 3 / 4 * log 2 + 250F (2 ^ k) = K / 4 + 250. Therefore, ∑ f (2 ^ k) = (1 + n) n / 8 + 250nk-n

How to compare the 0.4 power of 0.3 with the 0.3 power of 0.4?

0.3 ^ (0.4) = 0.3 ^ (4 / 10) = 0.0081 to the 10th power
0.4 ^ (0.3) = 0.4 ^ (3 / 10) = 0.064 to the 10th power
So 0.3 ^ (0.4) 0.4 ^ (0.3)

How many times is the result of negative square brackets with negative square brackets to the second degree

（-2）^100+(-2)^101
=2^100-2^101
=2^100(1-2)
=-（2^100）
It is the 100th power of bracket 2

If the 8th power of x = 16, then the 2nd power of x =? And the 4th power of x =?

The second power of x = 2
The fourth power of x = 4

The x power of 4 + the (x + 1) power of 3 * 2 - 16 > 0

Left = 2 ^ (2x) + 6.2 ^ x-16
Let t = 2 ^ x, then left = T & sup2; + 6t-16 (T > 0)
It is known from the title that T & sup2; + 6t-16 > 0, i.e. (T + 3) & sup2; > 25
∴t＞2
∴x＞1

If a (12 + x) (- 12 + x) = x4-116, then a=______ ．

∵ (12 + x) (- 12 + x) = x2-14, (x2 + 14) (x2-14) = x4-116, ∵ a = x2 + 14

The 1-log of y = x is based on 10, and the logarithm power of X (1

1000

What is the standard for sign changing when the x power of 0.9 is less than 1 / 3 to be converted into x > log0.9 (base number) 1 / 3 (true number)?
If less than becomes greater than, you want to change the sign by dividing it into negative numbers

Because the given exponent is the base of "the x power of function 0.9"

If x = 2 for a, x = 3 for B and x = 6 for C, what is x for ABC

Because logx a = 1 / loga x = 1 / 2, logx B = 1 / logb x = 1 / 3, logx C = 1 / logC x = 1 / 6
So logx a + logx B + logx C = logx (ABC) = 1 / 2 + 1 / 3 + 1 / 6 = 1
So logabc x = 1 / 1 = 1, that is, x with ABC as the base of log is 1