How to find the partial derivative of arctan (x, y) XY is a comma in the middle

z=arctan(x,y)
dz=dx/[1+(x,y)^2]+dy/[1+(x,y)^2]

Let z = u ^ 2lnv, and u = x / y, v = 3x-2y, find the lower partial derivative

If 2Sin (3x-2y + Z) = 3x-2y + Z, find x partial derivative + y partial derivative

Finding partial derivative DX of X
2cos(3x-2y+z)*3dx=3dx
dx=1/(2cos(3x-2y+z)*3-3)=1/(6cos(3x-2y+z)-3)
Finding partial derivative dy for y
2cos(3x-2y+z)*(-2dy)=-2dy
dy=1/(4cos(3x-2y+z)-2)

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