When z = x + 2Y + F (3x-4y), Z ▏ y = 0 = x ^ 2, find the partial derivative Z / partial derivative X and the partial derivative of Z to y 2 / 3 (3x-4y) and 10 / 3-8 / 9 (3x-4y)

Y = 0z = x + 2 * 0 + F (3x-0) = x ^ 2 = > x + F (3x) = x ^ 2 = > F (3x) = x ^ 2-x, that is, f (T) = T ^ 2 / 9-t / 3F '(T) = 2T / 9-1 / 3Z'x = x' + 2Y '+ F' (3x-4y) = 1 + 0 + (3x-4y) '* (2 * (3x-4y) / 9-1 / 3) = 1 + 3 * ((2x / 3-8y / 9) - 1 / 3) = 1 + 2x-8y / 3-1 = 2x-8y / 3 = 2 / 3 * (3x-4y

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