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Evaluation: x + 3Y divided into x-2y, 3x-5y = 0
3x-5y=0
3x=5y
x/y=5/3
(x-2y)/(x+3y)
=(x/y-2y/y)/(x/y+3y/y)
=(x/y-2)/(x/y+3)
=(5/3-2)/(5/3+3)
=(-1/3)/(14/3)
=-1/3*3/14
=-1/14
By substituting y = 2 / 3x-1 into the equation 2 / 3x-3y = 1, the solution of the equation is X=
Let y = 3x &; 1 / 2
Substitution equation
3x &; 3Y / 2 = 1
6x-3（3x-1）=4,
So, x = - 1 / 3,
So the answer is - 1 / 3
The first order equation with 2 variables is solved as follows: 5 / 2x-1 + 4 / 3y-2 = 0, 5 / 3x + 1 / 4 / 3y-2 = 0
fast
Add
(2x-1)/5+(3x+1)/5=0
5x/5=0
x=0
Put in the first one
-1/5+(3y-2)/4=0
3y-2=4/5
y=14/15
x=0,y=14/15
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