Finding the total differential of Z = in (XY) + e ^ (x + y ^ 2)

Finding the total differential of Z = in (XY) + e ^ (x + y ^ 2)

Let z = XY / (x ^ 2-y ^ 2), find the total differential when x = 2, y = 1, Δ x = 0.01, Δ y = 0.03

dz=d(xy/(x^2-y^2)=d(xy)/(x^2-y^2)-xy/(x^2-y^2)^2*d(x^2-y^2)=(ydx+xdy)/(x^2-y^2)
-XY / (x ^ 2-y ^ 2) ^ 2 (2xdx-2ydy) = (Y / (x ^ 2-y ^ 2) - 2x ^ 2Y / (x ^ 2-y ^ 2) ^ 2) DX + (x / (x ^ 2-y ^ 2) - 2XY ^ 2 / (x ^ 2-y ^ 2) ^ 2) dy, R and then you can do it yourself

How to find cos (XY) - x differential

For the differential of X, y is regarded as a constant. D / DX = - ysin (XY) - 1
For the differential of Y, X is regarded as a constant. D / dy = - xsin (XY)
Unless it's a space function, who are x, y, Z differential to?
In a word, there must be something wrong with your topic