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x+y+z=4 2x+3y-z=6 3x+2y+2z=10
X+Y+Z=4,
2 * (x + y + Z) + x = 10, we can get x = 2
4 + 3y-z = 66 + 2Y + 2Z = 10
So 3Y = Z + 2, 2Y + 2Z = 4
Y=1,X=1
X+Y+Z=4=2+1=1
2x+3y-z=6=4+3-1=6
3x+2y+2z=10=6+2+2
3x+2y=12.4 2x+3y=12.6 x=[ ] y=[ ]
Multiply both sides of the first equation by 2, and 6x + 4Y = 24.8
Multiply both sides of the second equation by 3 to get 6x + 9y = 37.8
Then the two equations are subtracted to get 5Y = 13, so y = 2.6
Then we substitute 3x + 2Y = 12.4 to get x = 2.4
So x = 2.4, y = 2.6
In fact, I want to ask this, z = e ^ x * siny, x = cosy, ask DZ / dy. ask for help~
This is a reference: DZ / DZ / dy =; Z /; Z /; Z /; y + (; Z /; Z /; Z /; Z /; Z /; y + (; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; Z /; X = _; X = x = x = E; DX / dy = - siny
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