The coefficient of (1 / x ^ 2) in the expansion of (x ^ 2 - (2 / x)) ^ 8 is

The coefficient of (1 / x ^ 2) in the expansion of (x ^ 2 - (2 / x)) ^ 8 is




The coefficient of (x ^ 2 + x-1) ^ 8 expansion with x ^ 5 term is
How do you get your coefficient? We only learned the binomial theorem.


X ^ 5 may be x ^ 5 (x ^ 2) x ^ 3 (x ^ 2) ^ 2x. According to the knowledge of permutation and combination, x ^ 5 means that five of the eight formulas choose x, and the remaining three choose (- 1), that is, C (5,8) * - 1) ^ 3 (x ^ 2) x ^ 3 means that one of the eight formulas chooses x ^ 2, and the remaining seven choose x ^ 2, and the remaining (- 1) coefficient is C (1,8) C (3,7) (- 1) ^ 4 (...)



Find the expansion of (1 + x) + (1 + x) ^ 2 + (1 + x) ^ 3 +... (1 + x) ^ 10 and the coefficient of x ^ 8


It is easy to know that x ^ 8 will appear only in (1 + x) ^ 8, (1 + x) ^ 9, (1 + x) ^ 10. By using the acquaintance theorem, the coefficient is 1 + 9 + 45 = 55



When B = 1, there are innumerable solutions to the equation a (3x-2) + B (2x-3) = 8x-7 about X


When B = 1, 3ax + 2x-3 = 8x-7
(3a+2-8)x=-4
3a+2-8=0
a=2



The equation a (3x-2) + B (2x-3) = 8x-7 about X is known. If B = 1 and the equation has a unique solution, the value of a is obtained


Take B = 1 into the equation,
The results show that: (3a-6) x = 2a-4
The equation has a unique solution, so 3A - 6 is not equal to 0, so a is not equal to 2



If the equation (a-6) x2-8x + 6 = 0 of X has real roots, then the maximum value of integer a is ()
A. 6B. 7C. 8D. 9


When a-6 = 0, i.e. a = 6, the equation is - 8x + 6 = 0, the solution is x = 68 = 34; when a-6 ≠ 0, i.e. a ≠ 6, △ = (- 8) 2-4 (a-6) × 6 = 208-24a ≥ 0, solve the above equation, a ≤ 263 ≈ 8.6, take the largest integer, i.e. a = 8



How to do the problem of X / 0.12 = 0.8? (use equation to solve it) please help me! Thank you!


X/0.12=0.8
x=0.8*0.12
x=0.096



How to solve the equation 3 (x + 2) = 4 (x + 1)? Urgent! Please help me!


3x+6=4x+4 4x-3x=6-4 x=2



How to solve 10 × 0.7x -- 10 (x-45) = (x-25) × 12 -- 12 (x-45)


7x-10x+450=12x-300-12x+540



How to solve the equation of 10% x + 85% (12-x) = 12 × 45%


10%x+85%(12-x)=12×45%
0.1x+10.2-0.85x=5.4
-0.75x=-4.8
x=-4.8÷0.75
x=6.4
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