7 and 4 / 5 △ 2 and 2 / 3 × (1 and 5 / 8 + 2 * x) - 1 and 1 / 10] - 2 / 15 △ 2 / 3 = 1.8 Such as the title

7 and 4 / 5 △ 2 and 2 / 3 × (1 and 5 / 8 + 2 * x) - 1 and 1 / 10] - 2 / 15 △ 2 / 3 = 1.8 Such as the title


39/5÷[8/3×﹙13/8+2x﹚-11/10]-2/15÷2/3=1.8
39/5÷[13/3+16x/3-1.1]-0.2=1.8
39/5÷[97/33+16x/3]=2
[97/33+16x/3]=39/10
16x/3=317/330
x=317/1760



Finding the minimum value of [x, x] and the maximum value of [x, x] = 6-6


F'(x)=3x^2-3
Let f '(x) = 0, then x = 1, or x = - 1. When x ∈ (0,1), f' (x)



Find the minimum value of function f (x) = √ (2x * 2-3x + 4) + √ (x * 2-2x)


The minimum value of F (x) is 2 when x = 0



7 X-12 = 58


10.7x-12=5810.7X=58+1210.7X=70X=70/10.7X=6.54



X 2 + 7 x + 10 = 0, how much is it to solve the equation x


x2+7x+10=0
(x+2)(x+5)=0
So x = - 2 or x = - 5



A few fractions, percentages of the Mathematical Olympiad, with the equation solution!
1. Number a is 1 / 2 of the sum of number B, number C and number d, number B is 1 / 3 of the sum of number a, number C and number d, and number C is 1 / 4 of the sum of number a, number B and number D. given number d is 260, find the sum of number a, number B, number C and number D
2. The sum of the numbers a and B is 300, and 2 / 5 of the number a is 55 more than 1 / 4 of the number B. what are the numbers a and B?
3. Yuhong primary school had 750 students in the first semester. This semester, male students increased by 1 / 6 and female students decreased by 1 / 5, with a total of 710. How many male and female students are there this semester?
4. Originally, the books on shelf a were 5 / 6 of those on shelf B. later, 60 books were moved from shelf a to shelf B. at this time, the books on shelf a were 9 / 13 of those on shelf B. how many books were there on each of the two shelves?
Use detailed equations to write!


1. Let a: A, B: B, C: C, D: then: B + C + D = 2A, a + C + D = 3b, a + B + D = 4C, so: a + B + C + D = 3A, a + B + C + D = 4b, a + B + C + D = 5C, that is: a = 1 / 3 (a + B + C + D), B = 1 / 4 (a + B + C + D), C = 1 / 5 (a + B + C + D) a + B + C + D = 1 / 3 (a + B + C + D) + 1 / 4 (a + B + C + D) + 1 / 5 (a + B + C + D) + 260a + B + C + D = 1



Ask some math questions and use proportion
1. Master Li plans to produce 450 parts. After 8 hours of work, 330 parts are still to be finished. At this speed, how many hours will it take to complete the task?
2. A printing factory plans to print 20000 textbooks in April, but it has printed 5600 textbooks in eight days. At this speed, how many textbooks can be printed in April?


1\(450-330):8=330:x
x=330*8/120=22
It takes 22 + 8 = 30 hours
2、8:5600=(30-8):x
x=15400
15400 + 5600 = 21000



Two math problems (all solved by equations)
1. Lao Wang deposits 5000 yuan in the bank for one year. When he withdraws at maturity, he will get 5080 yuan of capital and interest after deducting the interest tax. Given that the interest rate is 20%, what is the annual interest rate for one year?
2. A decoration company receives a business, if it takes 10 days for group A to complete, and 15 days for group B to complete. In order to complete the business as soon as possible, group A and group B will do it together. Four days later, group A has another task, and the rest will be done by group B alone. It will take several days to complete


Lao Wang deposits 5000 yuan in the bank for one year. He withdraws 5080 yuan after deducting the interest tax. What is the annual interest rate for one year, given that the interest rate is 20%? [5000 (1 + M%) ^ 1 - 5000] * (1-20%) = 50802. A decoration company receives a business, which takes 10 days for group A to complete and 15 days for group B to complete



Two mathematical problems should be solved by equations!
1. Xiaobin and Xiaoming run every morning. Xiaobin runs 4 meters per second and Xiaoming runs 6 meters per second
(1) If they start from the same place at the same time on the 400 meter runway and walk back to each other, will they meet in a few seconds?
(2) If two people start from the same place and walk in the same direction at the same time on the 400 meter runway, how many seconds later will they meet for the first time?
2. When a ship sails between two docks, it takes 4 hours to sail downstream and 5 hours to sail upstream. The water velocity is 2 kilometers per hour. Find out the speed of the ship sailing in still water


1. Set X seconds to meet
Then 4x + 6x = 400
10x=400
x=40
A: meet in 40 seconds
Let's meet in Y seconds
Then 6y-4y = 400
2y=400
y=200
A: meet in 200 seconds
2. The speed of sailing in still water is X
Then (x + 2) * 4 = (X-2) * 5
x=18
A: the speed of the ship in still water is 18 kilometers per hour