If log2 x is less than 1, then the value range of X is?

The value range of X is
0

Known function f (x) = 1-2a ^ x-a ^ 2x (a is greater than 1)
1： Finding the range of function f (x)
2： If x belongs to (- 2,1), the minimum value of function f (x) is - 7, find a and find the maximum value of function

Take the parameter t = a ^ x (a > 1), then there is: T > 0
f(t)=1-2t-t²
1、 According to the properties of quadratic function, when t = - (- 2) / [2 × (- 1)] = - 1, there is a maximum value, and the domain of T is t > 0

Given the function f (x) = - a2x-2ax + 1 (a > 1) (1) find the range of function f (x); (2) if x ∈ [- 2,1], the minimum value of function f (x) is - 7, find the value of A

(1) Let t = ax ＞ 0, ｜ f (x) = g (T) = - t2-2t + 1 = - (T + 1) 2 + 2 ∵ t ＞ 0, ｜ function be reduced on (0, + ∞) ｜ g (T) ＜ 1 ｜ function f (x) in the range of (- ∞, 1) (2) ∵ a ＞ 1, ｜ x ∈ [- 2, 1], t = ax ∈ [A-2, a], ∵ f (x) = g (T) = - t2-2t + 1 = - (T + 1) 2 + 2 ｜ function f (x) be reduced on [A-2, a] function f (x) is obtained When the minimum value ∵ x ∈ [- 2, 1], the minimum value of function f (x) is - 7, ∵ (a + 1) 2 + 2 = - 7 ∵ (a + 1) 2 = 9 ∵ a = 2 or - 4 (rounding off), so a = 2

If the product of polynomial MX & # 178; + nx-1 and X-2 is a cubic binomial of X, find the value of M, n

（mx²+nx-1）（x-2）
=mx³-2mx²+nx²-2nx-x+2
=mx³+（-2m+n）x²-（2n+1）x
+2
So, m ≠ 0,
-2m+n=0,
2n+1=0,
So, M = - 1 / 4
n=-1/2

If the product of polynomial (x2 + MX + 1) and (x + n) does not contain binomial about X, then the relationship between M and N is

M + n = 0 or m is not equal to n

When m, n satisfy what conditions, 7, the M-1 power of polynomial (2n-1) x-nx + 4 is a quadratic binomial of X?

Analysis: in order to make the original formula quadratic binomial, the first term must have, and the constant term can't offset positive and negative, so we can only let - NX = 0, so - n = 0, n = 0,
The highest number is 2, so M-1 = 2, M = 3
Conclusion: when m = 3, n = 0, the original formula is - x ^ 2 + 4, which is a quadratic binomial of X
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If the polynomial 1 / 2 x ^| n | - (n + 2) x + 7 is a quadratic binomial about X, then the value of n is___ (
If the polynomial 1 / 2 x ^| n | - (n + 2) x + 7 is a quadratic binomial about X, then the value of n is_
(2) Given A-B = 1 / 2, B-C = 2. Then the algebraic formula (A-C) ^ 2-2 (C-A) + 3 / 4 is .
(3) Given that the value of the algebraic formula x + 2Y is 3, then the value of the algebraic formula 2x + 4Y + 1 is 3 .
(4) After the price reduction of microwave oven by 25%, the price of each set is a yuan, the original price is__ .

The value of n is 2
twelve
seven
Four Thirds a

If the polynomial 2x ^ n - (M + n) x + 2 is a cubic binomial, then Mn=

2X ^ n - (M + n) x + 2 is a cubic binomial
n=3
m+n=0
m=-3
∴mn=-9
∵ on the surface, there are three terms. In the question, there is a binomial, so there is no one term. Only the coefficient of X is a letter, so it can only be m + n = 0
Cubic, so only n = 3
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If the polynomial 3x ^ (n + 1) - x ^ n + 2x ^ (m-1) can be transformed into a binomial of degree six, the value of 2n ^ 2-3m + 1 can be obtained

The formula 3x ^ (n + 1) - x ^ n + 2x ^ (m-1) can be changed into a binomial of degree six
So n + 1 = 6, n = 5,
2X ^ (m-1) is similar to x ^ 6 or x ^ 5
Ψ M-1 = 6 or M-1 = 5
‖ M = 7 or M = 6
When m = 7,
2n^2-3m+1=2*25-21+1=30
When m = 6,
2n^2-3m+1=2*25-18+1=33

If log2 x is less than 1, then the value range of X is?